Posted by Kyle on Wednesday, December 8, 2010 at 1:36am.
I am stuck...
find the real solutions of the equation
x to the 4th power minus 20x squared plus 64 equals 0

Algebra  drwls, Wednesday, December 8, 2010 at 2:17am
It is easier to do algebra if you write equations like that as follows:
x^4 20x^2 +64 = 0
Make a substitution y = x^2 and you have
y^2 20y +64 = 0
which can be factored to give
(y 16)(y4) = 0
The solutions are:
y = x^2 = 4 or 16
So
x = +2, 2, +4 and 4.
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