Saturday
March 25, 2017

Post a New Question

Posted by on .

I am stuck...
find the real solutions of the equation
x to the 4th power minus 20x squared plus 64 equals 0

  • Algebra - ,

    It is easier to do algebra if you write equations like that as follows:
    x^4 -20x^2 +64 = 0
    Make a substitution y = x^2 and you have

    y^2 -20y +64 = 0
    which can be factored to give
    (y -16)(y-4) = 0
    The solutions are:
    y = x^2 = 4 or 16
    So
    x = +2, -2, +4 and -4.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question