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To what volume should you dilute 131 mL of an 8.20 M CuCl2 solution so that 49.0 mL of the diluted solution contains 4.53g CuCl2 ?

  • Chemistry...Help!! -

    Molar mass of CuCl2 is 134.5 g mol^-1

    so solution needs to contain

    4.53 g / 134.5 g mol^-1
    =0.03368 mole

    concentration is

    0.049 L/0.03368 mole
    =1.455 molar

    thus we need to dilute the 8.20 M solution by a factor
    8.20 M/1.455 M= 5.636

    so the new total volume is

    131 ml x 5.636
    =738.4 ml

    check on the concentration

    old solution contains
    131 x 8.20 mmoles = 1074 mmoles

    new solution contains
    1.455 x 738.4 mmole = 1074 mmole

  • Chemistry...Help!! -

    Thank you for all the detail, but i'm still 738.4mL is the answer?

  • Chemistry...Help!! -

    Thank you :)

  • Chemistry...Help!! -

    this answer is incorrect. The following should be switched:

    0.049 L/0.03368 mole
    =1.455 molar

    should be
    0.03368 mol/0.049 L
    =0.6873 molar

    the rest of the steps are correct but you would need to substitute the above number in for the remainder of the problem

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