Posted by **Lisa, Help needed!** on Tuesday, December 7, 2010 at 11:12pm.

To what volume should you dilute 131 mL of an 8.20 M CuCl2 solution so that 49.0 mL of the diluted solution contains 4.53g CuCl2 ?

- Chemistry...Help!! -
**Dr Russ**, Wednesday, December 8, 2010 at 4:43am
Molar mass of CuCl2 is 134.5 g mol^-1

so solution needs to contain

4.53 g / 134.5 g mol^-1

=0.03368 mole

concentration is

0.049 L/0.03368 mole

=1.455 molar

thus we need to dilute the 8.20 M solution by a factor

8.20 M/1.455 M= 5.636

so the new total volume is

131 ml x 5.636

=738.4 ml

check on the concentration

old solution contains

131 x 8.20 mmoles = 1074 mmoles

new solution contains

1.455 x 738.4 mmole = 1074 mmole

- Chemistry...Help!! -
**Lisa, Help needed!**, Wednesday, December 8, 2010 at 1:59pm
Thank you for all the detail, but i'm still confused......so 738.4mL is the answer?

- Chemistry...Help!! -
**Anonymous**, Friday, January 20, 2012 at 7:10pm
Thank you :)

- Chemistry...Help!! -
**na**, Tuesday, September 18, 2012 at 7:11pm
this answer is incorrect. The following should be switched:

0.049 L/0.03368 mole

=1.455 molar

should be

0.03368 mol/0.049 L

=0.6873 molar

the rest of the steps are correct but you would need to substitute the above number in for the remainder of the problem

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