Posted by Lisa, Help needed! on Tuesday, December 7, 2010 at 11:12pm.
To what volume should you dilute 131 mL of an 8.20 M CuCl2 solution so that 49.0 mL of the diluted solution contains 4.53g CuCl2 ?

Chemistry...Help!!  Dr Russ, Wednesday, December 8, 2010 at 4:43am
Molar mass of CuCl2 is 134.5 g mol^1
so solution needs to contain
4.53 g / 134.5 g mol^1
=0.03368 mole
concentration is
0.049 L/0.03368 mole
=1.455 molar
thus we need to dilute the 8.20 M solution by a factor
8.20 M/1.455 M= 5.636
so the new total volume is
131 ml x 5.636
=738.4 ml
check on the concentration
old solution contains
131 x 8.20 mmoles = 1074 mmoles
new solution contains
1.455 x 738.4 mmole = 1074 mmole

Chemistry...Help!!  Lisa, Help needed!, Wednesday, December 8, 2010 at 1:59pm
Thank you for all the detail, but i'm still confused......so 738.4mL is the answer?

Chemistry...Help!!  Anonymous, Friday, January 20, 2012 at 7:10pm
Thank you :)

Chemistry...Help!!  na, Tuesday, September 18, 2012 at 7:11pm
this answer is incorrect. The following should be switched:
0.049 L/0.03368 mole
=1.455 molar
should be
0.03368 mol/0.049 L
=0.6873 molar
the rest of the steps are correct but you would need to substitute the above number in for the remainder of the problem
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