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Posted by on Tuesday, December 7, 2010 at 11:05pm.

What is the molarity of ZnCl2 that forms when 30.0g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 285 mL . (please explain step by step I have no clue!)

Zn(s) + CuCl2(aq) --> ZnCl2(aq)+ Cu(s)

  • Chemisty.....Help =)) - , Wednesday, December 8, 2010 at 4:48am

    From the equation 1 mole of Zn(s) gives 1 mole of ZnCl2(aq)

    Number of moles of Zn is mass/molar mass of Zn
    30.0 g /65.39 g mole^-1
    =0.4588 mole

    so 0.4588 mole ZnCl2 is formed (because 1 mole of Zn(s) gives 1 mole of ZnCl2(aq))

    which is in 285 ml final volume

    molarity is moles/volume (in L)

    molarity =
    0.4588 mole/0.285 L

  • Chemisty.....Help =)) - , Saturday, March 7, 2015 at 2:23pm

    l.64

  • Chemisty - , Sunday, November 8, 2015 at 11:47am

    the answer is approximately 1.6098 M

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