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October 1, 2014

October 1, 2014

Posted by **Anna** on Tuesday, December 7, 2010 at 8:43pm.

I don't know what equation to use or anything for this problem. Please help :) It is much appreciated!

- Calculus -
**Reiny**, Tuesday, December 7, 2010 at 9:10pmthe equation must be

x^2 + y^2 = 1

(since .6^2 + .8^2 = 1)

2x dx/dt + 2y dy/dt = 0

divide by 2 and substitute

.6(3) + .8 dy/dt = 0

dy/dt = -1.8/.8 = - 9/4 or - 2.25

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