Posted by Shannon on Tuesday, December 7, 2010 at 8:40pm.
i will do the first, you do the second
1. set y = 0
0 = -0.00545x^2 + 1.145x
0.00545x^2 - 1.145x = 0
x(0.00545x - 1.145) = 0
x=0 (at the start) or
x = 1.145/0.00545 = 210.1
2 max of y would be at the vertex of the parabola.
the x of the vertex is -b/2a = -1.145/(2(-0.00454)) = 105.05
then max y = -0.00545(105.05)^2 + 1.145(105.05)
= 60.14
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