A sample of ammonina gas at 65.5 degrees celsius and 524 torr has avolume of 15.31 L. What is it's volume at -15.8 degrees celsius and its pressure is 524 torr?

11.6 L

To solve this problem, we can use the combined gas law equation:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:
P1 = Initial pressure
V1 = Initial volume
T1 = Initial temperature
P2 = Final pressure
V2 = Final volume
T2 = Final temperature

In this case, we are given:
P1 = 524 torr
V1 = 15.31 L
T1 = 65.5 degrees Celsius (which needs to be converted to Kelvin)
P2 = 524 torr
T2 = -15.8 degrees Celsius (which also needs to be converted to Kelvin)

Now let's go step by step to solve the problem:

Step 1: Convert temperatures to Kelvin.
To convert Celsius to Kelvin, we use the equation:
T(K) = T(°C) + 273.15

T1(K) = 65.5 + 273.15 = 338.65 K
T2(K) = -15.8 + 273.15 = 257.35 K

Step 2: Plug the values into the combined gas law equation.

(P1 * V1) / (T1) = (P2 * V2) / (T2)

(524 torr * 15.31 L) / (338.65 K) = (524 torr * V2) / (257.35 K)

Step 3: Solve for V2.

Cross multiply and rearrange the equation to solve for V2:

(524 torr * V2) = (524 torr * 15.31 L * 257.35 K) / (338.65 K)

V2 = (524 torr * 15.31 L * 257.35 K) / (524 torr * 257.35 K)

V2 = 15.31 L

Therefore, the volume at -15.8 degrees Celsius and a pressure of 524 torr is 15.31 L, which is the same as the initial volume.