What is the density of CO2 gas at -25.2 degrees celsius and 98.0kPa?
2.09
To find the density of CO2 gas at a specific temperature and pressure, we can make use of the ideal gas law and the equation for density.
The ideal gas law states PV = nRT, where:
- P is the pressure,
- V is the volume,
- n is the number of moles,
- R is the ideal gas constant (8.314 J/(mol·K)),
- T is the temperature in Kelvin.
The equation for density is density = mass/volume, where:
- mass is the mass of the CO2 gas (in grams),
- volume is the volume of the CO2 gas (in liters).
To solve this problem, we need to convert the given temperature of -25.2 degrees Celsius to Kelvin. The Kelvin temperature scale is obtained by adding 273.15 to the Celsius temperature. So, -25.2 degrees Celsius is equal to 247.95 Kelvin.
Next, we can plug the values into the ideal gas law equation. Since we want to find the density, we need to manipulate the equation. The equation can be rearranged as:
density = (mass*P) / (R*T)
Now we need to consider the molar mass of CO2, which is approximately 44.01 g/mol.
To calculate the density of CO2 gas at -25.2 degrees Celsius and 98.0 kPa, we need to follow these steps:
1. Convert the Celsius temperature to Kelvin: 247.95 K
2. Plug in the values:
- Temperature (T) = 247.95 K
- Pressure (P) = 98.0 kPa (convert to Pa: 98,000 Pa)
- Ideal gas constant (R) = 8.314 J/(mol·K)
- Molar mass of CO2 (molar mass) = 44.01 g/mol
3. Solve the equation for density:
density = (molar mass * P) / (R * T)
By calculating the above equation, you should get the density of CO2 gas at the given conditions.