at 20 degrees celsius, how much sodium chloride could be dissolved in 2 L of water?
To determine the maximum amount of sodium chloride (NaCl) that can be dissolved in 2 liters of water at 20 degrees Celsius, we need to look at the solubility of NaCl in water at that temperature.
One way to find this information is by consulting a solubility table or a reference book that provides solubility data for different substances. The table should give you the solubility of NaCl in grams per 100 milliliters (g/100 mL) of water at various temperatures.
However, since we are given the volume in liters, we need to convert it to milliliters before using the solubility data.
1 liter of water is equivalent to 1000 milliliters (mL). So, in this case, we have 2 liters, which is equivalent to 2000 milliliters (2 L * 1000 mL/L = 2000 mL).
Now, let's assume the solubility of NaCl in water at 20 degrees Celsius is 35 grams per 100 milliliters (35 g/100 mL).
To find the maximum amount of NaCl that can be dissolved in 2000 mL of water, we can set up a proportion:
35 g / 100 mL = X g / 2000 mL
First, we cross-multiply:
(35 g) * (2000 mL) = (100 mL) * (X g)
Then, divide both sides by 100 mL to solve for X:
(35 g) * (2000 mL) / (100 mL) = X g
X ≈ 700 g
Therefore, at 20 degrees Celsius, approximately 700 grams of sodium chloride could be dissolved in 2 liters of water.