WHAT IS THE FREEZING POINT OF THIS SOLUTION?
25.5g C7,H11,N,O7,S(4-nitro-2-toluenesulfonic acid dihydrate) in 1.00x10^2g H2O(nonionizing solute)
compute the freezing point of this solution 1.00 x10^2 g c10h8o6s2
What is the boiling point of 25.5 g C7H11NO7S 4-nitro-2-toluenesulfonoicacid dihydrate in 1.00 X 102 g H2O non?
To determine the freezing point of a solution, you need to know the concentration and properties of the solute.
Given the composition of the solution: 25.5g of C7,H11,N,O7,S(4-nitro-2-toluenesulfonic acid dihydrate) in 100g of H2O, we can calculate the molality (number of moles of solute per kilogram of solvent).
1. Calculate the molar mass of C7,H11,N,O7,S:
- C (7 atoms) = 12.01 g/mol x 7 = 84.07 g/mol
- H (11 atoms) = 1.008 g/mol x 11 = 11.09 g/mol
- N (1 atom) = 14.01 g/mol x 1 = 14.01 g/mol
- O (7 atoms) = 16.00 g/mol x 7 = 112.00 g/mol
- S (1 atom) = 32.07 g/mol x 1 = 32.07 g/mol
Total molar mass = 84.07 + 11.09 + 14.01 + 112.00 + 32.07 = 253.24 g/mol
2. Calculate the number of moles of C7,H11,N,O7,S:
- Moles = Mass / Molar mass
- Moles = 25.5g / 253.24 g/mol = 0.1007 mol
3. Calculate the molality (moles per kilogram of solvent):
- Molality = Moles of solute / Mass of solvent (in kg)
- Mass of solvent = 100g = 0.1 kg
- Molality = 0.1007 mol / 0.1 kg = 1.007 mol/kg
Once you have the molality, you can use the freezing point depression constant (Kf) to calculate the freezing point change.
4. Find the freezing point depression constant (Kf) for water. This value depends on the solvent used. For water, Kf = 1.86 °C/m (degrees Celsius per molal).
5. Calculate the freezing point depression (ΔTf):
- ΔTf = Kf * molality
- ΔTf = 1.86 °C/m * 1.007 mol/kg = 1.87122 °C
Finally, subtract the freezing point depression from the normal freezing point of water (0 °C) to get the freezing point of the solution.
6. Freezing point of the solution = 0 °C - 1.87122 °C = -1.87122 °C
Therefore, the freezing point of the given solution is approximately -1.87122 °C.