WHAT IS THE BOILING POINT OF THIS SOLUTION?

1.00x10^2g C10,H8,O6,S2 (1,5-naphthalenedisulfonic acid) in 1.00x10^2g H2O (nonionizing solute)

-6.25

-6.25

To determine the boiling point of the solution, we need to find the molality of the solute.

Step 1: Calculate the moles of C10,H8,O6,S2 (1,5-naphthalenedisulfonic acid):
Given mass of 1,5-naphthalenedisulfonic acid = 1.00x10^2 g
Molar mass of 1,5-naphthalenedisulfonic acid (C10,H8,O6,S2) = 252.29 g/mol

moles = mass / molar mass
moles = 1.00x10^2 g / 252.29 g/mol

Step 2: Calculate the molality of the solution:
Molality (m) = moles of solute / mass of solvent (kg)
Given mass of H2O (solvent) = 1.00x10^2 g
Convert mass of H2O to kg: 100 g = 0.1 kg

Molality (m) = moles of 1,5-naphthalenedisulfonic acid / mass of H2O (kg)
Molality (m) = moles / 0.1 kg

Now, if we knew the boiling point elevation constant (kb) for the solvent, we could use the equation:

ΔTb = kb * m

Where ΔTb is the boiling point elevation, kb is the boiling point elevation constant, and m is the molality of the solution. However, since the kb value for H2O is not given, we cannot calculate the boiling point elevation or the boiling point of the solution.

To determine the boiling point of the solution, we need to consider the colligative properties, specifically boiling point elevation. The boiling point of a solution is higher than that of the pure solvent due to the presence of solute particles.

The boiling point elevation depends on the concentration of the solute and the number of particles it dissociates into in the solvent. In this case, we have 1.00x10^2g of 1,5-naphthalenedisulfonic acid (C10,H8,O6,S2) dissolved in 1.00x10^2g of water (H2O), which does not dissociate into ions.

To calculate the boiling point elevation, we can use the following formula:

ΔTb = Kb * m

Where:
ΔTb = boiling point elevation
Kb = molal boiling point constant (specific to the solvent, in this case, water)
m = molality of the solution

First, we need to find the molality (m) of the solution. Molality is defined as the number of moles of solute per kilogram of solvent.

To find the number of moles of 1,5-naphthalenedisulfonic acid (C10,H8,O6,S2), we need to calculate its molar mass. By adding the atomic masses of each element present in the compound, we get:

(10 * 12.01 g/mol) + (8 * 1.01 g/mol) + (6 * 16.00 g/mol) + (2 * 32.07 g/mol) = 316.26 g/mol

Next, we can calculate the moles of 1,5-naphthalenedisulfonic acid:

moles = mass / molar mass
moles = 1.00x10^2g / 316.26 g/mol

Similarly, we calculate the moles of water:

moles = mass / molar mass
moles = 1.00x10^2g / 18.02 g/mol

Since we know the mass of water is identical to its volume (in ml), we can convert the volume of water to kilograms (assuming the density of water is 1 g/ml).

mass of water = volume of water = 1.00x10^2g
mass of water = 1.00x10^2g / 1000 = 0.1 kg

Finally, we can calculate the molality of the solution:

m = moles of solute / mass of solvent in kg

Now that we have the molality (m), we can proceed to calculate the boiling point elevation (ΔTb) using the value for the molal boiling point constant (Kb) for water.

After finding ΔTb, we add it to the boiling point of pure water (100°C) to get the boiling point of the solution.