Posted by Tina P on Tuesday, December 7, 2010 at 10:20am.
Let the foot be x ft from the wall, let the angle formed by the ladder at the ground be Ų
given: dx/dt = 2 ft/s
find: dŲ/dt when x = 5
x/10 = cosŲ
x = 10cosŲ
dx/dt = -10sinŲ dŲ/dt
when x=5,
height^2 + 5^2 = 10^2
height = √75
2 = -10(√75/10) dŲ/dt
dŲ/dt = - 2/√75 radians/second
= appr. - .23 rad/s
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