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When four people with a combined mass of 320 kg sit down in a car, they find that the car drops 0.80 cm lower on its springs. Then they get out of the car and bounce it up and down. What is the frequency of the car's vibration if its mass (when it is empty) is 2.0 x 10^3 kg?

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    Use the additional compression distance (0.0080 m), due to added tha weight of 320 kg*g, to determine the spring constant, k, in units of N/m.

    k = 3136 N/.0008 m = ____

    The frequency of car vibration is then

    f = [1/(2 pi)]*sqrt(k/M)

    where M = 2000 kg

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