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November 28, 2014

November 28, 2014

Posted by **Queen** on Tuesday, December 7, 2010 at 8:03am.

- Chemistry -
**MathMate**, Tuesday, December 7, 2010 at 8:30amtime

= -(half life)*ln(fraction remaining)/ln(2)

= -(12.3)*(0.34)/ln(2)

= 19.1 years.

- Chemistry -
**Queen**, Tuesday, December 7, 2010 at 9:09amthanks a lot :)

- Chemistry -
**brian**, Thursday, July 26, 2012 at 12:24pmCesium-137 has a half life of 30.0 years. If initially there are 8.0 kg of cesium-137 present in a sample, how many kg will remain after 60.0 years?

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