Posted by **Steve** on Tuesday, December 7, 2010 at 12:07am.

A sign is supported at its top right corner, point P. The sign is a square with 40 cm on each side and has 8.0 kg mass. What is the magnitude of the horizontal force that P experiences?

- Physics -
**MathMate**, Tuesday, December 7, 2010 at 9:33am
If the sign is supported *only* at P, it requires a moment connection and there is no horizontal force.

Assume that the sign is supported at P and the bottom of the same side (40 cm down) is butted against the support.

Take moments:

mg * (40/2) = P*40

Solve for P.

- Physics -
**Yas**, Thursday, April 21, 2011 at 12:56pm
Where did the 40/2 come from?

- Physics -
**BasedGod**, Wednesday, April 24, 2013 at 1:40pm
40/2 Came from Steve's answer, get with it.

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