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April 18, 2015

April 18, 2015

Posted by **jessica** on Monday, December 6, 2010 at 9:55pm.

- college physics -
**Damon**, Monday, December 6, 2010 at 10:20pmacceleration down slope = w^2 R cos 10

so m a = m w^2 R cos 10

Force down slope = m g sin 10 + mu m g cos 10

so

g sin 10 + mu g cos 10 = w^2 R cos 10

g tan 10 + mu g = w^2 R

mu = ( w^2 r/g -tan 10)

= 0.201

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