Posted by help on .
an arrow of mass .04 kg is pulled back 10 cm in the bow, having a force of 25.2 N. It is released 1.5m from the ground...how far will the arrow fly?
(all of the energy from pulling it back converts into the flying arrow)
This problem is missing information.
If the pull force is constant:
pulled 0.10 meters * 25.2 = 2.52 Joules
.5 m u^2 = 2.52 Joules
solve for u
however if the bow behaves like a spring
then average force = 1/2 * max force
and we get 1.26 Joules
You do not say which
If you fire horizontally
solve vertical problem to find time in air
(1/2) g t^2 = 1.5 meters
solve for t
horizontal distance = u t
If you fire up at 45 degrees (max range) it is a little more complicated but again solve the vertical problem for time, then do the horizontal problem for distance.