# Calc

posted by
**Brandon** on
.

Find an equation of the tangent line to the graph of the function at the given point.

1 + ln xy = e^(x-y), (1,1)

posted by
**Brandon** on
.

Find an equation of the tangent line to the graph of the function at the given point.

1 + ln xy = e^(x-y), (1,1)