If 60 grams of KCl can be dissolved in 100 grams water. Would the remaining solution be unsaturated, saturated, or supersaturated?

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To determine if the remaining solution is unsaturated, saturated, or supersaturated, we need to compare the amount of solute (KCl) dissolved to the maximum amount of solute that can be dissolved in the given amount of solvent (water).

In this case, we have 60 grams of KCl dissolved in 100 grams of water. To determine if this solution is unsaturated, saturated, or supersaturated, we need to find the solubility of KCl in water.

To find the solubility of KCl, we can look up the solubility data for KCl in water. The solubility of KCl in water is approximately 34 grams per 100 grams of water at room temperature.

Comparing this solubility value to the amount of KCl dissolved in the solution (60 grams), we can see that the solution is saturated because it contains more solute (KCl) than the maximum amount that can be dissolved in the given amount of solvent (water). Thus, the remaining solution is saturated.