Posted by Michelle on Monday, December 6, 2010 at 7:28pm.
D^2=f(x)= (x-1)^2+((2x-4)-3)^2
f'(x)= 2(x-1)(1)+2(2x-7)(2)
0= 2x-2+(4x-14)2
0= 2x-2+8x-28
0= 10x-30
30=10x
x=3
y=2(3)-4
y=2
(3,2)
the square over D doesn't matter.
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