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December 21, 2014

December 21, 2014

Posted by **Michelle** on Monday, December 6, 2010 at 7:28pm.

- Calculus -
**rafay**, Tuesday, December 7, 2010 at 1:26amD^2=f(x)= (x-1)^2+((2x-4)-3)^2

f'(x)= 2(x-1)(1)+2(2x-7)(2)

0= 2x-2+(4x-14)2

0= 2x-2+8x-28

0= 10x-30

30=10x

x=3

y=2(3)-4

y=2

(3,2)

the square over D doesn't matter.

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