What is the concentration of a H2SO4 solution if 10.0 mL of the solution is neutralized by
7.8 mL of a 0.20 M NaOH solution?
7.8 mL of 0.20M NaOH contains 0.0078*0.20 = 0.00156 mole of NaOH
But
H2SO4+2NaOH = Na2SO4 + 2H2O
So 0.00156 mole of NaOH will neutralize 0.00156/2=0.00078 mole of H2SO4 contained in 10mL.
So concentration of H2SO4 = 0.00078/0.0100
= 0.078M
Well, let's do some clown math here! 🤡
To find the concentration of the H2SO4 solution, we can use the equation:
C1V1 = C2V2
Where:
C1 = concentration of NaOH solution = 0.20 M
V1 = volume of NaOH solution = 7.8 mL
C2 = concentration of H2SO4 solution
V2 = volume of H2SO4 solution = 10.0 mL
So, rearranging the equation, we have:
C2 = (C1 x V1) / V2
Now, plug in the values:
C2 = (0.20 M x 7.8 mL) / 10.0 mL
Calculating this, we get:
C2 = 0.156 M
Therefore, the concentration of the H2SO4 solution is approximately 0.156 M. 🤡
To determine the concentration of the H2SO4 solution, we can use the concept of stoichiometry and the neutralization reaction between H2SO4 and NaOH.
First, let's write the balanced chemical equation for the neutralization reaction:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
From the balanced equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, the mole ratio between H2SO4 and NaOH is 1:2.
Given that 10.0 mL of the H2SO4 solution is neutralized by 7.8 mL of a 0.20 M NaOH solution, we need to find the moles of NaOH used.
Step 1: Convert the volume of NaOH solution to moles.
moles NaOH = volume (L) x concentration (mol/L)
moles NaOH = 0.0078 L x 0.20 mol/L
moles NaOH = 0.00156 mol
Step 2: Use the mole ratio between H2SO4 and NaOH to determine the moles of H2SO4.
moles H2SO4 = 0.00156 mol NaOH x (1 mol H2SO4 / 2 mol NaOH)
moles H2SO4 = 0.00078 mol
Step 3: Convert the moles of H2SO4 to concentration (mol/L) using the volume of the H2SO4 solution.
concentration (mol/L) = moles H2SO4 / volume (L)
concentration (mol/L) = 0.00078 mol / 0.010 L
concentration (mol/L) = 0.078 M
Therefore, the concentration of the H2SO4 solution is 0.078 M.
To find the concentration of a solution, we can use the concept of stoichiometry and the equation:
acid (H2SO4) + base (NaOH) → salt + water
Here, the stoichiometric ratio between H2SO4 and NaOH is 1:2. This means that one mole of H2SO4 reacts with two moles of NaOH.
Let's start by calculating the number of moles of NaOH that reacted:
moles of NaOH = concentration (M) × volume (L)
moles of NaOH = 0.20 M × 0.0078 L
moles of NaOH = 0.00156 mol
Since the stoichiometric ratio between H2SO4 and NaOH is 1:2, the number of moles of H2SO4 will be twice that of NaOH:
moles of H2SO4 = 2 × 0.00156 mol
moles of H2SO4 = 0.00312 mol
The volume of the H2SO4 solution is given as 10.0 mL. For the purpose of calculations, let's convert it to liters:
volume of H2SO4 solution = 10.0 mL = 0.0100 L
Now, we can find the concentration (M) of the H2SO4 solution:
concentration (M) = moles of H2SO4 / volume of H2SO4 solution
concentration (M) = 0.00312 mol / 0.0100 L
concentration (M) = 0.312 M
Therefore, the concentration of the H2SO4 solution is 0.312 M.