Posted by Ivy on Monday, December 6, 2010 at 5:27pm.
7.8 mL of 0.20M NaOH contains 0.0078*0.20 = 0.00156 mole of NaOH
But
H2SO4+2NaOH = Na2SO4 + 2H2O
So 0.00156 mole of NaOH will neutralize 0.00156/2=0.00078 mole of H2SO4 contained in 10mL.
So concentration of H2SO4 = 0.00078/0.0100
= 0.078M
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