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What is the concentration of a H2SO4 solution if 10.0 mL of the solution is neutralized by
7.8 mL of a 0.20 M NaOH solution?

  • Chemistry -

    7.8 mL of 0.20M NaOH contains 0.0078*0.20 = 0.00156 mole of NaOH
    H2SO4+2NaOH = Na2SO4 + 2H2O
    So 0.00156 mole of NaOH will neutralize 0.00156/2=0.00078 mole of H2SO4 contained in 10mL.
    So concentration of H2SO4 = 0.00078/0.0100
    = 0.078M

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