Posted by Nia on Monday, December 6, 2010 at 5:16pm.
friction work= 6N*35M=210joules.
finalKE= initialKE-210
1/2 m vf^2=1/2 m vi^2-210
Vf^2= vi^2-2*210
vi= 7 m/s
Related Questions
COLLEGE PHYSICS - A 62.0 kg skier is moving at 6.50 m/s on a frictionless, ...
physics - A 69 kg skier encounters a dip in the snow's surface that has a ...
science - A 71.9-kg skier coasts up a snow-covered hill that makes an angle of ...
physics - A 64.2-kg skier coasts up a snow-covered hill that makes an angle of ...
physics - A 64.9 kg skier coasts up a snow-covered hill that makes an angle of ...
physics - A 64.9 kg skier coasts up a snow-covered hill that makes an angle of ...
Physics 1 - A 64.9 kg skier coasts up a snow-covered hill that makes an angle of...
Physics - A 61.8 kg skier coasts up a snow-covered hill that makes an angle of ...
physics - A 65.0-kg skier coasts up a snow-covered hill that makes an angle of ...
physics 2..help PLEASE!! - A 63 kg skier encounters a dip in the snow's ...
For Further Reading