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posted by Melanie on Monday, December 6, 2010 at 5:13pm.
27x^3-8=0 (difference of two cubes)
27x^3-8=0 (3x - 2)(x^2 + 6x + 4) = 0 x = 2/3 or x = ... (2 imaginary roots) use the quadratic equation formula to find the 2 complex roots.
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