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December 20, 2014

December 20, 2014

Posted by **Melanie** on Monday, December 6, 2010 at 5:13pm.

(difference of two cubes)

- algebra 2 -
**Reiny**, Monday, December 6, 2010 at 5:47pm27x^3-8=0

(3x - 2)(x^2 + 6x + 4) = 0

x = 2/3 or x = ... (2 imaginary roots)

use the quadratic equation formula to find the 2 complex roots.

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