Posted by jessica on Monday, December 6, 2010 at 1:48pm.
One cm of a 10cmlong rod is made of metal, and the rest is wood. The metal has a density of 5000kg/m^3 and the wood has a density of 500kg/m^3. When the rod is set into pure water, the metal part points downward. How much of the rod is underwater?

college physics  bobpursley, Monday, December 6, 2010 at 2:19pm
well, you know the metal will all be underwater. So the question is how much wood is under to support the weight of the metal.
bouyancy of wood= h*density water*area*g
that has to equal the weight of the entire rod.
h*densitywater(area)g.1*densitymetal*g(area h*denstiywood*area*g=0
dividing out area, g; divideing by density water.
h.1spgrmetalhspgrwood=0
h= (.1 spgrmetal)/(1+sprgwood)= about .5/(1.5)=33cm ?
check my work.
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