algebra
posted by Lost .
How do I solve for x on both sides of the equation, i.e. 72x+48=42x12? Is there a standard way of figuring this out?

72x+48=42x12
First, subtract 42x from both sides.
72x  42x + 48 = 42x  42x  12
30x + 48 = 12
Then subtract 48 from both sides.
30x = 48 + (12)
30x = 60
x = 60/30
x = 2