Post a New Question

algebra

posted by on .

How do I solve for x on both sides of the equation, i.e. 72x+48=42x-12? Is there a standard way of figuring this out?

  • algebra - ,

    72x+48=42x-12

    First, subtract 42x from both sides.

    72x - 42x + 48 = 42x - 42x - 12
    30x + 48 = -12

    Then subtract 48 from both sides.

    30x = -48 + (-12)
    30x = -60
    x = -60/30
    x = -2

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question