Posted by
**Marium** on
.

An oil droplet with a mass of 3.50 x 10^-15 kg accelerates downward at a rate of 2.50 m/s2 when it is between two horizontal charged plates that are 1.00 cm apart. Assuming that the excess charge on the droplet is negative and the top plate is positive, how many excess electrons does the droplet carry if the potential difference between the plates is 533 V?

Is this the equation I should be using..?

E = v/d

q E = m g

If I use the above eqs. I get the wrong answer =(

Plz help!! and thank you in advance! =)