Posted by Josh on .
Evaluate all six trigonometric functions at t, where the given point lies on the terminal side of an angle of t radians in standard position. (40/41, 9/41)

Precalculus Someone please help 
bobpursley,
draw the triangle, but first, scale it (that wont change the angle). (40,9) works. That makes the hypotenuse sqrt(40^2+9^2)=41
so you have a triangle, in the fourth quadrant sides 40, 9, with a hypotenuse of 41
sin= 9/41
cos= 40/41
You take it from here. 
Precalculus Someone please help 
Reiny,
You know you are in quadrant IV
by CAST, the cosine, (and the secant), are positive in that quadrant. All other trig ratios are negative.
You also know you are dealing with a 94041 rightangled triangle, since 9^2 + 40^2 = 41^2.
so x=40, y = 9 , and r = 41
Now you can state the other 5 trig ratios.
e.g. tan t = 9/41 (because tanĂ˜ = y/x, etc) 
oops typo  Precalculus Someone please help 
Reiny,
e.g. tan t = 9/40