Homework Help: college

Posted by tanika on Monday, December 6, 2010 at 1:39am.

suppose that you have 800ft of fencing. you are to construct a rectangular corral which is divided into two pieces. what are the dimensions that give the largest possible areas?

math (calculus) - drwls, Monday, December 6, 2010 at 3:11am
The way to divide a rectangle in two pieces using minimum fence materials is to build a third fence segment having the width dimension, W,in the middle somewhere. The rectangle length L is then given by
3W + 2L = 800, so
L = 400 - 3/2 W

Area = L*W = 400W -(3/2)W^2
dA/dW = 0 = 400 - 3W
W = 133 1/3 ft ; L = 200
gives maximum area

Answer this Question

Related Questions

Math / Algebra Word Problem - The Parkhursts used 160 yd of fencing to enclose a...
MATH problem help had typo - The Parkhursts used 160 yd of fencing to enclose a ...
Calculus - A rancher has 900 meters of fence to enclose a rectangular corral. ...
Precalculus - A barn has 150 feet of fencing and there are 3 rectangular corrals...
CALC HARD... - Suppose that 430 ft of fencing is used to enclose a corral in the...
math help please - I had 12 of these problems got thru all but the last one. I ...
CALC HARD... - Suppose that 430 ft of fencing is used to enclose a corral in the...
CALC HARD... - Suppose that 430 ft of fencing is used to enclose a corral in the...
calculus - Suppose that 430 ft of fencing is used to enclose a corral in the ...
Precalculus - A barn has 150 feet of fencing and there are 3 rectangular corrals...

For Further Reading

First Name:
School Subject:
Answer: