Posted by **tanika** on Monday, December 6, 2010 at 1:39am.

suppose that you have 800ft of fencing. you are to construct a rectangular corral which is divided into two pieces. what are the dimensions that give the largest possible areas?

- math (calculus) -
**drwls**, Monday, December 6, 2010 at 3:11am
The way to divide a rectangle in two pieces using minimum fence materials is to build a third fence segment having the width dimension, W,in the middle somewhere. The rectangle length L is then given by

3W + 2L = 800, so

L = 400 - 3/2 W

Area = L*W = 400W -(3/2)W^2

dA/dW = 0 = 400 - 3W

W = 133 1/3 ft ; L = 200

gives maximum area

## Answer this Question

## Related Questions

- College Algebra - A rancher wishes to enclose a rectangular partitioned corral ...
- Algebra - A rancher wishes to enclose a rectangular partitioned corral with 1932...
- Maths - You have 400 meters of fencing to use to make a rectangular enclosure. ...
- Math / Algebra Word Problem - The Parkhursts used 160 yd of fencing to enclose a...
- College Algebra - A farmer needs to build a rectangular corral for his animals. ...
- cal - a rancher has 4000 feet of fencing for constructing a rectangular corral. ...
- area and perimet - Farmer Brown has 700 yards of fencing with which to build a ...
- MATH problem help had typo - The Parkhursts used 160 yd of fencing to enclose a ...
- math - Suppose you have enough material for 60 feet of fencing. With this ...
- math - a rectangular pen is divided into 6 rectangular strips by fences running ...

More Related Questions