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December 18, 2014

December 18, 2014

Posted by **Mack** on Monday, December 6, 2010 at 1:28am.

a. Ho :

b. Ha :

c. Critical value(s) =

d. Test statistic =

e. Approximate P-value =

f. Decision:

Interpret this decision:

- Statistics -
**Anonymous**, Monday, December 6, 2010 at 11:10ama non-normal population is determined to have a mean of 60 and a standard deviation of 4. Ninety-six percent of all observed values will occur in what range?

- Statistics -
**PsyDAG**, Tuesday, December 7, 2010 at 9:47pmAssume a normal distribution.

Ho: mean = 219 mg/100 ml

Ha: mean ≠ 219 mg/100 ml

c. Z > ± 1.645

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion

- Statistics anon. -
**PsyDAG**, Tuesday, December 7, 2010 at 9:52pmFirst, if you have a question, it is much better to put it in as a separate post in <Post a New Question> rather than attaching it to a previous question, where it is more likely to be overlooked.

If it is not normal, the assumptions applied to a normal distribution will be in error. However, for a normal distribution, this is what you would want.

Mean ± 2.055 SD

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