Calculus
posted by Jane on .
∫4 [( ( ln(z) )^ 2)/z] dz
∫[( 7 e^(7 √x))/ √x] dx
∫[(2 x + 5)/( x^2 + 5 x + 2)] dx

Let x^2 +5x +2 = u
That makes du = (2x +5) dx
So your integral becomes du/u = ln u = ln (x^2 + 5x + 2)
Try a similar substitution technique with the others.