Homework Help: Calculus

Posted by Erika on Sunday, December 5, 2010 at 11:46pm.

Find the integral by substitution

∫ [(16 x3)/(x4 + 5)] dx

∫[ 4 x/(√{x2 + 3})] dx

∫ 8 x2 e4 x3 +7 dx

PLEASE help with all three. i'd really appreciate it

Calculus - MathMate, Monday, December 6, 2010 at 9:32am
Hints:
1. if u=x⁴+5
du/dx
=d(x⁴+5)/dx
=4x³
or du = 4x³ dx

2. u=√{x² + 3}
du/dx = x/√{x² + 3}
du = xdx/√{x² + 3}

3. u=?
8x²e⁴/(x³ +7)

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