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Posted by on Sunday, December 5, 2010 at 11:46pm.

Find the integral by substitution

∫ [(16 x3)/(x4 + 5)] dx

∫[ 4 x/(√{x2 + 3})] dx

∫ 8 x2 e4 x3 +7 dx

PLEASE help with all three. i'd really appreciate it

  • Calculus - , Monday, December 6, 2010 at 9:32am

    Hints:
    1. if u=x4+5
    du/dx
    =d(x4+5)/dx
    =4x³
    or du = 4x³ dx

    2. u=√{x² + 3}
    du/dx = x/√{x² + 3}
    du = xdx/√{x² + 3}

    3. u=?
    8x²e4/(x³ +7)

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