How much 2.5mM solution of NaCl can be made from 30g of this pure salt?
Molar mass NaCl = 58.442
30.0 g is 30.0/58.442 = 0.5133 moles.
2.5 mM = 0.0025M
M = moles/L of soln.
0.0025 = 0.5133/L of soln
Solve for L.
To determine how much 2.5mM solution of NaCl can be made from 30g of pure salt, we first need to calculate the molar mass of NaCl.
NaCl consists of one sodium atom (Na) and one chlorine atom (Cl). The atomic mass of Na is approximately 23 grams/mol, while the atomic mass of Cl is approximately 35.5 grams/mol.
Hence, the molar mass of NaCl can be calculated as follows:
Molar mass of NaCl = (23g/mol for Na) + (35.5g/mol for Cl)
Molar mass of NaCl = 58.5g/mol
Now, we can calculate the number of moles of NaCl in 30g of the salt using the formula:
Number of moles = Mass / Molar mass
Number of moles of NaCl = 30g / 58.5g/mol
Number of moles of NaCl ≈ 0.512 mol
Since the provided solution concentration is given in mM (millimolar), we need to convert 2.5mM to mol/L (molar concentration). To convert millimolar to molar, divide by 1000.
Molar concentration (Mol/L) = 2.5mM / 1000
Molar concentration ≈ 0.0025 mol/L
Now, to determine the volume of the solution, we can use the equation:
Volume (L) = Number of moles / Molar concentration
Volume (L) = 0.512 mol / 0.0025 mol/L
Volume (L) ≈ 204.8 L
Therefore, from 30g of pure NaCl, approximately 204.8 liters of a 2.5mM NaCl solution can be made.