Tuesday
March 28, 2017

Post a New Question

Posted by on .

a buffer is prepared by mixing .208 L of 0.452 M HCl and 0.5 L of 0.4 M sodium acetate. When the Ka= 1.8 x 10^-5

I figured out that the pH= 4.74

but then it asks how many grams of KOH must be added to the buffer to change the pH by .155 units?

  • Chemistry- Buffers - ,

    Show me how you obtained pH = 4.74. I can't get that. My answer looked more like 4.79.

  • Chemistry- Buffers - ,

    Since Ka a measure of H+ ions,
    -log(Ka)= pH.. my assignment says that part is right, I just don't know what to do from there to get M -> moles -> grams

  • Chemistry- Buffers - ,

    -log Ka = pKa which may or may not be = pH. Ka is a measure of how strong/weak the acid is.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question