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Posted by on Sunday, December 5, 2010 at 9:45pm.

The premiters of two equilateral triangles are in the ratio 2:3. If the perimeter of the smaller triangle is 16 cm what is the measure of a side of the larger triangle?

  • Math Please Help - , Sunday, December 5, 2010 at 9:51pm

    Permimeter is a linear ratio (3:2), and ratio of sides is also a linear ratio (3:2). SO if the shorter is 16, the longer one is 16*3/2=?

  • Math Please Help - , Sunday, December 5, 2010 at 10:06pm

    could I do it in a proportion?

  • Math Please Help - , Sunday, December 5, 2010 at 10:17pm

    Yes, you could do it in proportion as long as both measurements are linear, e.g. perimeter and side.

  • Math Please Help - , Sunday, December 5, 2010 at 10:20pm

    how?

  • Math Please Help - , Sunday, December 5, 2010 at 10:23pm

    ...SO if the shorter is 16, the longer one is 16*3/2=?

  • Math Please Help - , Sunday, December 5, 2010 at 10:26pm

    I got 10 something but it's not one of the answers

  • Math Please Help - , Sunday, December 5, 2010 at 10:29pm

    16*3/2 has to be greater than 16, how did you get 10?

  • Math Please Help - , Sunday, December 5, 2010 at 10:34pm

    3/2 = .6 repaeating x 16 = 10.6 repeating

    and 16/1 x 2/3 = 10.6 reapeating

  • Math Please Help - , Sunday, December 5, 2010 at 10:37pm

    3/2 = 3 divided by 2 = 1.5
    Think of
    (16*3)/2 = ?
    That should make it easier!

  • Math Please Help - , Sunday, December 5, 2010 at 10:39pm

    But that equals 24 and that not a answer on the thing

  • Math Please Help - , Sunday, December 5, 2010 at 10:42pm

    Sorry, I misread the question (too fast).
    The perimeter of the smaller triangle is 16 cm, so the perimeter of the larger triangle should be 24 as you calculated. However, since 24 is the perimeter of three equal sides, each side should measure 24/3=8 cm.
    Make sure you understand how it is to be done, or else you will get stuck on the next problem.

  • Math Please Help - , Sunday, December 5, 2010 at 10:43pm

    Ok I get it. Thank you!!!

  • Math - , Sunday, December 5, 2010 at 10:44pm

    Also, it would help if you could give your first name or a pen-name of your choice so next time I would know we worked together before.

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