Posted by Please Help! on Sunday, December 5, 2010 at 9:45pm.
The premiters of two equilateral triangles are in the ratio 2:3. If the perimeter of the smaller triangle is 16 cm what is the measure of a side of the larger triangle?

Math Please Help  MathMate, Sunday, December 5, 2010 at 9:51pm
Permimeter is a linear ratio (3:2), and ratio of sides is also a linear ratio (3:2). SO if the shorter is 16, the longer one is 16*3/2=?

Math Please Help  Please Help!, Sunday, December 5, 2010 at 10:06pm
could I do it in a proportion?

Math Please Help  MathMate, Sunday, December 5, 2010 at 10:17pm
Yes, you could do it in proportion as long as both measurements are linear, e.g. perimeter and side.

Math Please Help  Please Help!, Sunday, December 5, 2010 at 10:20pm
how?

Math Please Help  MathMate, Sunday, December 5, 2010 at 10:23pm
...SO if the shorter is 16, the longer one is 16*3/2=?

Math Please Help  Please Help!, Sunday, December 5, 2010 at 10:26pm
I got 10 something but it's not one of the answers

Math Please Help  MathMate, Sunday, December 5, 2010 at 10:29pm
16*3/2 has to be greater than 16, how did you get 10?

Math Please Help  Please Help!, Sunday, December 5, 2010 at 10:34pm
3/2 = .6 repaeating x 16 = 10.6 repeating
and 16/1 x 2/3 = 10.6 reapeating 
Math Please Help  MathMate, Sunday, December 5, 2010 at 10:37pm
3/2 = 3 divided by 2 = 1.5
Think of
(16*3)/2 = ?
That should make it easier! 
Math Please Help  Please Help!, Sunday, December 5, 2010 at 10:39pm
But that equals 24 and that not a answer on the thing

Math Please Help  MathMate, Sunday, December 5, 2010 at 10:42pm
Sorry, I misread the question (too fast).
The perimeter of the smaller triangle is 16 cm, so the perimeter of the larger triangle should be 24 as you calculated. However, since 24 is the perimeter of three equal sides, each side should measure 24/3=8 cm.
Make sure you understand how it is to be done, or else you will get stuck on the next problem. 
Math Please Help  Please Help!, Sunday, December 5, 2010 at 10:43pm
Ok I get it. Thank you!!!

Math  MathMate, Sunday, December 5, 2010 at 10:44pm
Also, it would help if you could give your first name or a penname of your choice so next time I would know we worked together before.