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August 29, 2014

August 29, 2014

Posted by **linda** on Sunday, December 5, 2010 at 8:03pm.

- algebra -
**Reiny**, Sunday, December 5, 2010 at 8:44pm2.1t^2 - 82t + 95 = 15

2.1t^2 - 82t + 80 = 0

solve using the quadratic equation formula, I got

t = 1.00 or t =38.05

- algebra -
**Carole**, Sunday, December 5, 2010 at 8:54pmN=2.1t^2- 82t+95 Since N = 15,

15=2.1t^2- 82t+95 Now get this quadratic into standard form by subtracting 15 from both sides

15-15= 2.1t^2- 82t+95-15

0=2.1t^2- 82t+80 I am not sure what methods you have studied to solve this yet, but I would use the quadratic equation. Where a = 2.1, b = 82 and c = 80

t= (-b}(b^2-4ac))/2a

t= (-82}6052)/(2(2.1))

t = -1.00 or -38.04

Largest would be -1.00

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