Saturday

April 19, 2014

April 19, 2014

Posted by **H** on Sunday, December 5, 2010 at 5:36pm.

- Pre -calculus -
**Reiny**, Sunday, December 5, 2010 at 6:02pmheight at beginning of observation:

tan 21° = h/2 ----> height = 2tan21 = .76773

height after 5 seconds:

tan 35° = h/2 ----> height = 1.40042

change in height = .63269

average vertical speed = .63269/5 = .12654 km/s

so in 15 seconds it will have risen 1.89061 km on top of the .76773 km , its original height

so new height = 2.66579

tanØ = 2.66278/2 = 1.3328955..

Ø = 53.12°

**Related Questions**

Precalculus - An observer 2 km from the launching pad observes a vertically ...

Math - A rocket shoots straight up from the launch-pad. Five seconds after lift...

Maths - Please I need help.Iam stuck with this question.Using sine and cosine ...

Math (Pre-Calc) - An airplane is flying east at a constant altitude of 28,000 ...

math - A rocket shoots straight up from the launch pad.Five seconds after lift ...

Math help - A rocket shoot straight up from the launch pad. Five seconds after ...

Math - An observer 2.5 miles from the launch pad of a space shuttle measures the...

Math - An observer 2.5 miles from the launch pad of a space shuttle measures the...

physics - I am having so much trouble with this D: A rocket is traveling ...

calculus - A rocket rises vertically from a point on the ground that is 100m ...