Posted by **H** on Sunday, December 5, 2010 at 5:36pm.

An observer 2 km from the launching pad observes a vertically ascending missile at an angle of elevation of 21 degrees. 5 seconds later the nagle has increased to 35 degrees. What was its average speed during this interval? If it keeps going vertically at the same average speed, what will its angle of elevation be 15 seconds after the first sighting?

- Pre -calculus -
**Reiny**, Sunday, December 5, 2010 at 6:02pm
height at beginning of observation:

tan 21° = h/2 ----> height = 2tan21 = .76773

height after 5 seconds:

tan 35° = h/2 ----> height = 1.40042

change in height = .63269

average vertical speed = .63269/5 = .12654 km/s

so in 15 seconds it will have risen 1.89061 km on top of the .76773 km , its original height

so new height = 2.66579

tanØ = 2.66278/2 = 1.3328955..

Ø = 53.12°

## Answer This Question

## Related Questions

- Precalculus - An observer 2 km from the launching pad observes a vertically ...
- Math - A rocket shoots straight up from the launch-pad. Five seconds after lift...
- Calculus - A rocket is fired vertically into the air at the rate of 6 miles/min...
- Math (Pre-Calc) - An airplane is flying east at a constant altitude of 28,000 ...
- math - A rocket shoots straight up from the launch pad.Five seconds after lift ...
- Math help - A rocket shoot straight up from the launch pad. Five seconds after ...
- Math - An aircraft which is maintaining a constant altitude of 1000 meters is ...
- physics - I am having so much trouble with this D: A rocket is traveling ...
- math - an airplane is flying at a constant altitude of 28000 meters. when first ...
- Maths - Please I need help.Iam stuck with this question.Using sine and cosine ...

More Related Questions