Posted by Jimmy on Sunday, December 5, 2010 at 4:49pm.
The sum of heats gained is zero.
origmasswater*c*(t-30)+newmassadded*c*(t-15)=0
because the density of the rain and pool water is the same, as is the width and length, you can do this wiht depths.
depth originally= 2500/(50*30)
new depth= .005m added.
2500/(50*30)(t-30)+.005(T-15)=0
solve for t
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