Posted by andrew on .
what equation would you use if you wanted to find the net x-direction force on the box
example: here is the problem...
A box of mass 24.0 kg is subject to an applied force of 245 N with a depression angle of 31.2°, and it accelerates to the right. The horizontal surface has a coefficient of friction μ = 0.245.
What is the net x-direction force on the box?
first find friction;
friction= mu*fnormal= mu(mg+245sinTheta)
then find the horizontal component of force fhorz= 245*cosTheta
net force= horizontal-friction