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Posted by on Sunday, December 5, 2010 at 1:07pm.

What volume of 0.115M NaOH is required to reach the equivalence point in the titration of 25.00 mL of 0.200M of HF?
Ka(HF)=7.4 x 10^-4

  • chemistry - , Sunday, December 5, 2010 at 2:29pm

    Ka is not needed.
    mL x M = mL x M.

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