sorry How many moles of exygen are needed to react with 1.6 moles of isopropyl alcohol, C3H7OH Equation is 2 C3H7OH + 9 02 -> 6 CO2 + 8 H20
Use the coefficients in the balanced equation to convert moles of one thing into moles of anything else.
1.6 moles isopropyl alcohol x (9 moles O2/2 mol isopropyl alc) = 1.6*(9/2) = ??
To determine how many moles of oxygen are needed to react with 1.6 moles of isopropyl alcohol (C3H7OH), we need to use the stoichiometry of the chemical equation you provided.
The balanced equation is:
2 C3H7OH + 9 O2 -> 6 CO2 + 8 H2O
From the equation, we can see that the molar ratio between isopropyl alcohol (C3H7OH) and oxygen (O2) is 2:9.
To calculate the moles of oxygen needed, we can set up a proportion using the molar ratio:
(1.6 moles C3H7OH / X) = (2 moles C3H7OH / 9 moles O2)
Now, let's solve for X (the number of moles of oxygen needed):
Cross-multiplying, we get:
1.6 moles C3H7OH * 9 moles O2 = 2 moles C3H7OH * X
Rearranging the equation:
X = (1.6 moles C3H7OH * 9 moles O2) / 2 moles C3H7OH
Calculating:
X = 7.2 moles O2
Therefore, 7.2 moles of oxygen are needed to react with 1.6 moles of isopropyl alcohol.