Math
posted by Name on .
if the angle between the two lines 3x5y1=0 and Kxy=3 is 45, then find the value of k

m1 = tanA = 3 /5 = 0.6,
tanA = 0.6,
A = 31 deg.
B = 31 + 45 = 76 deg.
m2 = tanB,
m2 = tan76 = 4.0
m2 = K / 1 = 4,
K / 1 = 4,
Cross multiply:
K =  4,
K = 4.