If you collect hydrogen gas over water at a temperature of 45 degrees celcius, what is the volume of jst te hydrogen if the pressure of hydrogen is 1.23 atm and the grams of hydrogen was 2.6? What is the volume of the water?

You don't make it clear if the pressure of the WET hydrogen is 1.23 atm or the pressure of the DRY hydrogen is 1.23. If it is dry, then use PV = nRT and use 1.23 for pressure. If it is WET, look up vapor pressure H2O @ 45 C, convert to atm, and subtract from the 1.23 and use that in PV = nRT. The volume of water is done use PV = nRT also but use vapor pressure of the water to find volume water.

To find the volume of hydrogen gas collected over water, we need to use the Ideal Gas Law, which states:

PV = nRT

Where:
P = Pressure of the gas in atmospheres (atm)
V = Volume of the gas in liters (L)
n = Number of moles of the gas
R = Ideal gas constant, which is 0.0821 L·atm/(mol·K)
T = Temperature of the gas in Kelvin (K)

First, we need to convert the temperature from Celsius to Kelvin using the equation:
T(K) = T(°C) + 273.15

Given:
Temperature (T) = 45°C = 45 + 273.15 = 318.15 K
Pressure (P) = 1.23 atm

Next, we need to calculate the number of moles (n) of hydrogen gas using the given mass (grams) of hydrogen.

To find the number of moles, we'll use the formula:
n = m / M

Where:
m = mass of the gas in grams
M = molar mass of the gas in grams/mole

Given:
Mass of hydrogen (m) = 2.6 g

The molar mass of hydrogen (M) is approximately 2.016 g/mol.

Now let's calculate the number of moles (n):
n = 2.6 g / 2.016 g/mol ≈ 1.289 mol (rounded to 3 decimal places)

Now we have all the values needed to calculate the volume of hydrogen gas (V).

Rearranging the Ideal Gas Law equation to solve for volume, we have:
V = (nRT) / P

Substituting the known values:
V = (1.289 mol * 0.0821 L·atm/(mol·K) * 318.15 K) / 1.23 atm

Calculating this, the volume of hydrogen gas is approximately:
V ≈ 27.216 L (rounded to 3 decimal places)

Now, to determine the volume of water, we need additional information such as the height or depth of the water column. The volume of water cannot be calculated based solely on the information provided.