Posted by Anonymous on Saturday, December 4, 2010 at 9:48pm.
I need help with b... I found that k=.750880 for part a but I can't figure out what y would be to get potential energy.
A 52 g mass is attached to a massless spring and allowed to oscillate around an equilibrium according to:
y(t) = 0.8 * sin( 3.8 * t ) where y is measured in meters and t in seconds.
(a) What is the spring constant in N/m?
k = .750880 N/m
(b) What is the Total Energy in the mass and spring in J?
E = ???J
HELP: The total energy is the sum of the kinetic energy and potential energy. At what point in the motion is the energy all kinetic? At what point is it all potential? Can you compute it at this point?
HELP: Kinetic energy is 1/2 * Mass * v2
Potential energy is 1/2 * k * y2
We know that at the mass's maximum yposition it has zero velocity, so simply compute Potential Energy at that point.

Physics  Marco, Saturday, December 4, 2010 at 11:01pm
At equilibrium position, K.E.=max,P.E. = 0
At the two extreme points, K.E.=0,P.E.=max
Total energy is constant at ANY POINT.
We find E at extreme point.
E = 1/2*k*(0.8)^2
= 0.24J

Physics  Damon, Saturday, December 4, 2010 at 11:02pm
but you know the velocity
dy/dt = .8 * 3.8 cos (3.8 t)
maximum velocity when sin (3.8 t) = 1
si
max Ke = total = (1/2) (.052)(.8*3.8)^2

Physics  Marco, Saturday, December 4, 2010 at 11:10pm
lol, both method can find the answer
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