Posted by **Brittany** on Saturday, December 4, 2010 at 7:30pm.

The airplane can take off when its airspeed (speed of the air flowing over the wing) is equal to 65 knots. What is the length of runway required for the plane to take off if there is a 21 knots head wind? The runway at the Tallahassee Regional Airport has a length of 8000 ft.

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**bobpursley**, Saturday, December 4, 2010 at 7:43pm
change (65-21)knots to m/s. You can do that by putting this in the google search window:

(65-21)knots in m/s

Then

speedabove^2=2ad where d is the length of the runway (in meters), and I assume you messed up the problem, you are looking for acceleration a.

and, once you can find a, you can figure the thrust of the engines:

Thrust= mass*a

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**Brittany**, Saturday, December 4, 2010 at 7:53pm
so how would i go about finding acceleration?

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**bobpursley**, Saturday, December 4, 2010 at 7:56pm
a= .5*speed^2/distance

make certain your units are in meters, and seconds.

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**Brittany**, Saturday, December 4, 2010 at 8:06pm
thank u so much!! ^w^

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