Posted by danny123 on Saturday, December 4, 2010 at 6:05pm.
You solve the problem which ALWAYS comes out in Kelvin because you may use ONLY Kelvin in the solution. The volume doubles when the Kelvin T doubles and is halved when the Kelvin T is halved.
Doubling the celsius, by the way, will NOT double the volume and you can prove that by the following:
Suppose we let V1 = 10 mL, then
(V1/T1) = (V2/T2)
(10/20 K) = (V2/40 K)
V2 = 10mL*(40/20 = 20 mL (double T doubles V) BUT
from 20 celsius to 40 celsius is from 293 K to 313 K and
(10/293) = (V2/313)
V2 = 10 mL*(313/293) = 10.7 mL. See. Not even close.
thanks
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