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December 19, 2014

December 19, 2014

Posted by **lllll** on Saturday, December 4, 2010 at 5:20pm.

foci: (±4, 0) asymptotes: y= +/- 3x

- Precalc -
**Reiny**, Saturday, December 4, 2010 at 5:32pmwe know c=4 and b/a = 3/1 so b = 3a

also in a standard hyperbola

a^2 + b^2 = c^2

a^2 + (9a^2) = 16

a^2 = 16/10 = 8/5

b^2 = 9a^2 = 72/5

standard form:

x^2/((8/5) - y^2/((72/5)) = 1

- Precalc -
**lllll**, Saturday, December 4, 2010 at 6:20pmThank you!!I was just having a hard time on finding out a and b but now I understand.

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