Posted by **Qay** on Saturday, December 4, 2010 at 4:21pm.

Find the rotational kinetic energy and angular momentum about its axis of the earth due to its daily rotation. Let ME = 6 x 1024 kg, RE = 6.4 x 106 m and ùE = 1.157 x 10-5 rev/sec.

- physics -
**bark**, Saturday, December 4, 2010 at 4:45pm
angular momentum of earth = Ie*ùe

Putting ùe = 2ð/T = 2ð/(24*60*60) = 7.27*10^-5

If we assume average density of earth = 5500 kg/m³, and R = 6400 km,

Ie = 8ðñeR^5 / 15 (formula for moment of inertia (MOI) of sphere with density ñe and radius R)

Ie=9,9 * 10^22

angular momentum of earth = Ie*ùe

= 9,9 * 10^22* 7.27*10^-5= 7,2*10^18

## Answer This Question

## Related Questions

- physics - Find the rotational kinetic energy and angular momentum about its axis...
- physics - Find the rotational kinetic energy of the earth about the sun due to ...
- physics - Find the rotational kinetic energy of the earth about the sun due to ...
- phys - A disk rolls down a slope. It rotational axis is its center of mass. It ...
- Physics - An ice skater spins with her arms extended and then pulls her arms in...
- Physics- drwls please help - (a) Calculate the kinetic energy that the earth has...
- college physics - In the figure below, two particles, each with mass m = 0.82 kg...
- Physics - (a) Calculate the kinetic energy that the earth has because of its ...
- physics - An ice skater spins about a vertical axis at an angular speed of 15 ...
- physics - an ice skater spins about a vertical axis at an angular speed of 15 ...

More Related Questions