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March 30, 2015

March 30, 2015

Posted by **Qay** on Saturday, December 4, 2010 at 4:21pm.

- physics -
**bark**, Saturday, December 4, 2010 at 4:45pmangular momentum of earth = Ie*ùe

Putting ùe = 2ð/T = 2ð/(24*60*60) = 7.27*10^-5

If we assume average density of earth = 5500 kg/m³, and R = 6400 km,

Ie = 8ðñeR^5 / 15 (formula for moment of inertia (MOI) of sphere with density ñe and radius R)

Ie=9,9 * 10^22

angular momentum of earth = Ie*ùe

= 9,9 * 10^22* 7.27*10^-5= 7,2*10^18

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