Posted by Sue on Saturday, December 4, 2010 at 10:30am.
It does not matter how much oxygen is in the tank, the SO2 is formed from S in the tank and O in the atmosphere.
Each mole of S (32 g) will form 1 mole of SO2, with a mass of 64 g. Thus one g of SO2 will be formed from 0.5 g of S. That is 1/64 mole of SO2.
Since each mole at STP occupies 22.4 l, you will make 22.4/64 = 0.35 liters of SO2.
You should get the same result using
V = nRT/P , if you use the right R value, P, and T, with 1/64 mole.
Your answer will be in liters, not atm.
THANKS!!!
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