Posted by Gee on .
A large wooden wheel of radius R and the moment of inertia I is mounted on an axle so as to rotate freely. A bullet of mass m and speed v is shot tangential to the wheel and strike its edge, lodging in the wheelâ€™s rim. If the wheel was originally at rest, what is its rotation rate just after the collision?

physics 
drwls,
Initial angular momentum about axis =
Mbullet*Vbullet*R
This equals the final angular momentum,
(Iwheel + Mbullet*R^2)*w_final
w_final = (Mbullet*Vbullet)*R/(Iwheel + Mbullet*R^2)