Saturday

July 26, 2014

July 26, 2014

Posted by **Maa** on Saturday, December 4, 2010 at 8:46am.

- physics -
**drwls**, Saturday, December 4, 2010 at 10:16amAngular acceleration = Torque/(moment of inertia)

The moment of inertia is (1/2) M R^2 for a disk.

After 10 seconds, the number of radians turned is

theta = (1/2)(angular acceleration)*(10 s)^2

Divide that by 2 pi for the number of revolutions.

Rotational work done is (torque)*(theta)

**Related Questions**

physics - A solid cylindrical disk has a radius of 0.17 m. It is mounted to an ...

Physics - A solid cylindrical disk has a radius of 0.18 m. It is mounted to an ...

physics - A solid cylindrical disk has a radius of 0.16 m. It is mounted to an ...

Physics - Figure 10-42 shows a uniform disk that can rotate around its center ...

phys - A disk with a rotational inertia of 2.0 kg.m^2 and a radius of 0.40 m ...

Physics - A disk with a mass of 13 kg, a diameter of 25 cm, and a thickness of 8...

Calc Physics - A disk with a mass of 17 kg, a diameter of 25 cm, and a thickness...

Physics - A disk with a mass of 18 kg, a diameter of 50 cm, and a thickness of 8...

Angular Velocity Question - A disk with a mass of 18 kg, a diameter of 50 cm, ...

physics - A horizontal 791 N merry-go-round is a solid disk of radius 1.48 m, ...