Posted by Farah on Saturday, December 4, 2010 at 5:16am.
1 a.u. = 1.40*10^8 km = 1.40*10^11 m
For the mass of the entire galaxy, M, you will have to assume a spherical distribution of mass, with the star in question at the outside, at distance R.
In that case, the centripetal acceleration of the star is
V^2/R = G M/R2
Solve for M.
M = R V^2/G
You did not type the distance R correctly. Is the "g" supposed to be a 9?
G is Newton's universal constant of gravity, 6.67*10^-11 N*m^2/kg^2
Related Questions
Physics - A star of mass 2.0 1028 kg that is 1.6 1020 m from the center of a ...
physics - A star of mass 2.0 1031 kg that is 4.8 1020 m from the center of a ...
Physics - Our Milky Way galaxy is very similar to our neighboring galaxy ...
Cosmology - magine you look through a really strong telescope and see a rich ...
Physics - The Hubble Space Telescope (HST) has recorded evidence of a black hole...
physics - The sun rotates around the center of the milky way galaxy at a ...
science - which of the statements below is true? a) the stars in a galaxy are ...
Astronomy - The apparent brightness of a Cepheid variable star in a far-away ...
ASTRONOMY - In which type of galaxy would you most likely to observe a massive ...
Cosmology - What observations were used by Edwin Hubble to show that the ...
For Further Reading